THE ELECTION OF 1860

In effect, two presidential campaigns took place in 1860. In the North, Lincoln and Douglas were the combatants. In the South, the Republicans had no presence and three candidates contested the election—Douglas, Breckinridge, and John Bell of Tennessee, the candidate of the hastily organized Constitutional Union Party. A haven for Unionist former Whigs, this new party adopted a platform consisting of a single pledge—to preserve “the Constitution as it is [that is, with slavery] and the Union as it was [without sectional discord].”

The most striking thing about the election returns was their sectional character. Lincoln carried all of the North except New Jersey, receiving 1.8 million popular votes (54 percent of the regional total and 40 percent of the national) and 180 electoral votes (a clear majority). Breckinridge captured most of the slave states, although Bell carried three Upper South states and about 40 percent of the southern vote as a whole. Douglas placed first only in Missouri, but his 1.3 million popular votes were second in number only to Lincoln’s. Douglas was the only candidate with significant support in all parts of the country, a vindication, in a sense, of his long effort to transcend sectional divisions. But his failure to carry either section suggested that a traditional political career based on devotion to the Union was no longer possible. Without a single vote in ten southern states, Lincoln was elected the nation’s sixteenth president. He failed to secure a majority of the national popular vote. But because of the North’s superiority in population, Lincoln would still have carried the electoral college and thus been elected president even if the votes of his three opponents had all been cast for a single candidate.

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